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Q)

$H_2O_2$ oxidises $H_2S$ to

$\begin{array}{1 1}(a)\;\text{S}\\(b)\;H_2SO_4\\(c)\;H_2S_2O_8\\(d)\;H_2SO_5\end{array}$

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A)
$H_2O_2+H_2S\rightarrow 2H_2O+S$
Hence (a) is the correct answer.