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An ideal gas occupies a volume V at temperature T and pressure P. The mass of each molecule is m. The molar mass of the gas is M. Then the temperature at which the sample of gas will weight m is given by which of the following options?

(A) $\large\frac{PV}{M}$ (B) $\large\frac{m}{PV}$ (C) $\large\frac{PVM}{mR} $ (D) $\large\frac{mR}{PVM} $

1 Answer

For any ideal gas, $PV = nRT = \large\frac{m}{M}$$RT$.
$\Rightarrow T = \large\frac{PVM}{mR}$
answered Jan 23, 2014 by balaji.thirumalai

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