logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class12  >>  Wave Optics
0 votes

In a young's double slit experiment the fringe width is $0.05\;mm$ when the distance of screen from slit is $75 \;cm$ . If the distance of screen from the slit is increased by $25 \;cm$ , the fringe width will be

$(a)\;0.66\;mm \\ (b)\;0.066\;mm \\ (c)\;6.0\;mm \\ (d)\;60\;mm $

Can you answer this question?
 
 

1 Answer

0 votes
$\large\frac{\beta '}{\beta} =\large\frac{\Large\frac{\lambda D'}{d}}{\Large\frac{\lambda D}{d}}$
$\qquad= \large\frac{D'}{D}$
$D= 75$
$D'= 75+25=100$
$\large\frac{\beta'}{\beta}= \large\frac{100}{75}$
$\beta' =0.05 \times \large\frac{4}{3}\; $$mm$
$\qquad=0.066 \;mm$
Hence b is the correct answer.
answered Jan 23, 2014 by meena.p
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...