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# In acidic solution $H_2O_2$ oxidises $Hg$ to

$\begin{array}{1 1}(a)\;Hg_2O\\(b)\;HgSO_4\\(c)\;HgS\\(d)\;HgO\end{array}$

In acidic solution $H_2O_2$ oxidises $Hg$ to $HgO$
Hence (d) is the correct option.