# $H_2O_2$ is obtained by action of dil $H_2SO_4$ on

$\begin{array}{1 1}(a)\;MnO_2\\(b)\;PbO_2\\(c)\;BaO_2\\(d)\;SnO_2\end{array}$

By the action of dilute sulphuric acid. Apaste of hydrated barium peroxide $(BaO_2.8H_2O)$ is prepared in ice – cold water and then added slowly to an ice-cold solution of $20\%\; H_2SO_4$
$BaO_2.8H_2O +H_2SO_4 \to BaSO_4+H_2O_2 +8H_2O$