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What is the oxidation state of Fe in the product formed when acidified pottasium ferrocyanide treated with $H_2O_2$?

$\begin{array}{1 1}(a)\;+2\\(b)\;+6\\(c)\;+1\\(d)\;+3\end{array}$

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$K_3[Fe(CN)_6]$ can be formed.In this Fe oxidation state is +3.
Hence (d) is the correct answer.
answered Jan 24, 2014 by sreemathi.v
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