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Atomic Structure
If the electron energy is -3.4 eV , Find the principal quantum number of H-atom?
$(a)\;3\qquad(b)\;1\qquad(C)\;2\qquad(d)\;4$
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asked
Jan 24, 2014
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sharmaaparna1
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Aug 7, 2014
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1 Answer
$E_n = \large\frac{E_1}{E_2}$
(Since $E_1$ for H-atom = -13.6 eV
Or $n^2 = \large\frac{E_1}{E_2}$
$= \large\frac{-13.6}{-3.4}=4$
$\therefore$ n = 2
Hence the answer is (c)
answered
Jan 24, 2014
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sharmaaparna1
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Jan 24, 2014
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