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Decomposition of $NaCl\rightarrow x+y$.They are

$\begin{array}{1 1}(a)\;Na^++Cl^-\\(b)\;Na^-+Cl^-\\(c)\;Na^++Cl^+\\(d)\;Na^-+Cl^-\end{array}$

1 Answer

$NaCl\rightarrow Na^++Cl^-$.
Hence $x+y\Rightarrow Na^++Cl^-$.
Hence (a) is the correct answer.
answered Jan 24, 2014 by sreemathi.v
 
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