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# $2Na+H_2\quad\underrightarrow{heat}\quad 2NaH$,$Ca+H_2\rightarrow CaH_2$,$2Li+H_2\rightarrow x$.Then $x$ is

$\begin{array}{1 1}(a)\;LiH_2\\(b)\;LiH_3\\(c)\;2LiH\\(d)\;LiH\end{array}$

$2Li+H_2\rightarrow 2LiH$.
Hence (c) is the correct answer.