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# $4LiH+AlCl_3\quad\underrightarrow{\text{dry ether}}\quad x+y$. $x$ is

$\begin{array}{1 1}(a)\;LiAlH_4\\(b)\;LiAlH_3\\(c)\;2LiAlH_3\\(d)\;LiH_2\end{array}$

$4LiH+AlCl_3\quad\underrightarrow{\text{dry ether}}\quad LiAlH_4+3LiCl$
Hence $x$ is $LiAlH_4$
Hence (a) is the correct answer.