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# The wrong state in the below about $H_2O_2$ is

$\begin{array}{1 1}(a)\;\text{Acts both as oxidising and reducing agent}\\(b)\;\text{Two OH bonds lie in the same plane}\\(c)\;\text{Pale blue liquid}\\(d)\;\text{Can be oxidised by }O_3\end{array}$

Two OH bonds lie in the same planes.
Hence (b) is the correct answer.