# $KIO_4$ is reduced to $KIO_4+H_2O_2\rightarrow$____________

$\begin{array}{1 1}(a)\;KIO_3\\(b)\;KIO_2\\(c)\;KIO\\(d)\;KI\end{array}$

$KIO_4$ is reduced to $KIO_4+H_2O_2\rightarrow KIO_3$
Hence (a) is the correct answer.
answered Jan 24, 2014