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Home  >>  JEEMAIN and AIPMT  >>  Chemistry  >>  Hydrogen
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$2K_3Fe(CN)_6+2KOH\rightarrow x+y+z$,$H_2O_2+z\rightarrow y+w$.The $z$ is

$\begin{array}{1 1}(a)\;O_2\\(b)\;O_3\\(c)\;O\\(d)\;O_2^-\end{array}$

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$2K_3Fe(CN)_6+2KOH\rightarrow 2K_4Fe(CN)_6+H_2O+O$
$H_2O_2+O\rightarrow H_2O+O_2$.
Hence z is $O$
Hence (c) is the correct answer.
answered Jan 24, 2014 by sreemathi.v
 
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