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# $2K_3Fe(CN)_6+2KOH\rightarrow x+y+z$,$H_2O_2+z\rightarrow y+w$.The $w$ is

$\begin{array}{1 1}(a)\;O_2\\(b)\;O_3\\(c)\;O_2^-\\(d)\;O_3^-\end{array}$

Can you answer this question?

$H_2O_2+O\rightarrow H_2O+O_2$
Hence w is $O_2$
Hence (a) is the correct answer.
answered Jan 24, 2014