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Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class11  >>  Statistics
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The A.M of 9 items is 15. If one more item is added to this series, the A.M becomes 16. The value of 10th item is

$\begin {array} {1 1} (A)\;23 & \quad (B)\;25 \\ (C)\;27 & \quad (D)\;30 \end {array}$

Can you answer this question?
 
 

1 Answer

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$ 15 = \large\frac{x_1+x_2+....+x_9}{9}$
$ \Rightarrow x_1+x_2+....x_9=135$
Also $ 16=\large\frac{x_1+x_2+....x_9+x_{10}}{10}$
$x_1+x_2+.....+x_9+x_{10}=160$
$x_{10}=160-135$
$ = 25$
Ans : (B)
answered Jan 25, 2014 by thanvigandhi_1
 

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