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# The A.M of 9 items is 15. If one more item is added to this series, the A.M becomes 16. The value of 10th item is

$\begin {array} {1 1} (A)\;23 & \quad (B)\;25 \\ (C)\;27 & \quad (D)\;30 \end {array}$

$15 = \large\frac{x_1+x_2+....+x_9}{9}$
$\Rightarrow x_1+x_2+....x_9=135$
Also $16=\large\frac{x_1+x_2+....x_9+x_{10}}{10}$
$x_1+x_2+.....+x_9+x_{10}=160$
$x_{10}=160-135$
$= 25$
Ans : (B)