$\begin {array} {1 1} (A)\;20 & \quad (B)\;40 \\ (C)\;60 & \quad (D)\;80 \end {array}$

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- $ \overline x = \large\frac{n_1\overline x _1+n_2\overline x _2}{n_1+n_2}$

$ \overline x = \large\frac{n_1\overline x _1+n_2\overline x _2}{n_1+n_2}$

$ 500 = \large\frac{n_1(520)+n_2(420)}{n_1+n_2}$

$ 500 (n_1+n_2)=520n_1+420n_2$

$ 500n_1+500n_2=520n_1+420n_2$

$ 500n_1-520n_1=420n_2-500n_2$

$ -20n_1=-80n_2$

$ \large\frac{n_1}{n_2} = \large\frac{\not{-}8\not{0}}{\not{-}2\not{0}}$

$ \large\frac{n_1}{n_2}=\large\frac{4}{1}$

$ \therefore$ percentage of male employees = 80

Ans : (D)

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