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Questions  >>  JEEMAIN and NEET  >>  Mathematics  >>  Class11  >>  Statistics
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Q)

Mean of 100 items is 49. It was discovered that 3 items 60, 70, 80 were wrongly read as 38,22,50 respectively. The correct mean is

$\begin {array} {1 1} (A)\;43 & \quad (B)\;78 \\ (C)\;50 & \quad (D)\;80 \end {array}$

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A)
Sum of 100 items = $ 49 \times 100$
$ = 4900$
Sum of wrong items = $ 38 + 22+50$
$ = 110$
Sum of correct items = $ 60+70+80$
$ = 210$
$ \therefore $ correct sum = $ 4900-110+210$
$ = 5000$
$ \therefore $ correct mean = $ \large\frac{5000}{100}$
$ = 50$
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