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The A.M of set of 50 numbers is 48. If two numbers 52 and 44 are discarded then A.M of the remaining set of numbers is
$\begin {array} {1 1} (A)\;50 & \quad (B)\;52 \\ (C)\;48 & \quad (D)\;44 \end {array}$
jeemain
math
cbse
class11
statistics
medium
measures-of-dispersion-(a.m)
q34
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asked
Jan 25, 2014
by
thanvigandhi_1
retagged
Sep 7, 2014
by
sharmaaparna1
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Total sum = $ 50 \times 48$
$ = 2400$
Discarding two numbers 52 and 44, the sum becomes $ 2400-(52+44)=2304$
New A.M = $ \large\frac{2304}{48}$
Average of 52 and 44 is 48
New A.M remains the same.
Ans : (C)
answered
Jan 25, 2014
by
thanvigandhi_1
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