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Sometimes yellow turbidity appears while passing $H_2S$ gas even in the absence of II group radicals. This is because

(a) Sulphur is present in the mixture as impurity
(b) IV group radicals are precipitated as sulphides
(c) of the oxidation of $H_2S$ gas by some acid radical
(d) III group radicals are precipitated as hydroxide

1 Answer

Answer:  of the oxidation of $H_2S$ gas by some acid radical
 
$H_2S + [O] \longrightarrow S\downarrow + H_2O$
        (For some  (Colloidal Sulphur)
oxidising radical)
answered Jan 25, 2014 by mosymeow_1
edited Jan 29, 2014 by mosymeow_1
 
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