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Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class11  >>  Statistics
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If variance of $ x_1, x_2,....x_n$ is $ \sigma^2$ then variance of $ ax_1, ax_2,.....ax_n ( a \neq 0)$ is

$\begin {array} {1 1} (A)\;\sigma^2 & \quad (B)\;a \sigma^2 \\ (C)\;a^2 \sigma^2 & \quad (D)\;\large\frac{\sigma^2}{a^2} \end {array}$

Can you answer this question?
 
 

1 Answer

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$ \sigma^2= \large\frac{1}{n}$ $ \Sigma (x-\overline x)^2$
New variance = $ \large\frac{1}{n} $ $ \Sigma ( ax - a \overline x)^2$
$ = a^2\sigma^2$
Ans : (C)
answered Jan 26, 2014 by thanvigandhi_1
 

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