# If in a frequency distribution, the mean and median are 21 and 22 respectively, then its mode is approximately

$\begin {array} {1 1} (A)\;22.0 & \quad (B)\;20.5 \\ (C)\;25.5 & \quad (D)\;24.0 \end {array}$

Mode $\pm$ 2 mean = 3 median
Mode = $3 \times 22 - 2 \times 21$
$= 66-42$
$= 24$
Ans : (D)