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Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class11  >>  Statistics
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If in a frequency distribution, the mean and median are 21 and 22 respectively, then its mode is approximately

$\begin {array} {1 1} (A)\;22.0 & \quad (B)\;20.5 \\ (C)\;25.5 & \quad (D)\;24.0 \end {array}$

Can you answer this question?
 
 

1 Answer

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Mode $ \pm $ 2 mean = 3 median
Mode = $ 3 \times 22 - 2 \times 21$
$ = 66-42$
$ = 24$
Ans : (D)
answered Jan 27, 2014 by thanvigandhi_1
 
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