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NaCl , NaBr and NaI mixture on heating with conc. $H_2SO_4$ gives gases respectively

(a) $HCl, Br_2, I_2$
(b) $HCl, HBr, HI$
(c) $Cl_2, Br_2, I_2$
(d) None of these
Can you answer this question?
 
 

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Answer: $HCl, Br_2, I_2$
$NaCl + H_2SO_4 \overset{\Delta}{\longrightarrow} NaHSO_4 + HCl \uparrow $
$HCl + H_2SO_4 \overset{\Delta}{\longrightarrow}$ No reaction
$NaBr + H_2SO_4 \overset{\Delta}{\longrightarrow} NaHSO_4 + HBr$
$2HBr + H_2SO_4 \overset{\Delta}{\longrightarrow} Br_2 \uparrow + SO_2 + 2H_2O$
$NaI + H_2SO_4 \overset{\Delta}{\longrightarrow} NaHSO_4 + HI$
$2HI + H_2SO_4 \overset{\Delta}{\longrightarrow} I_2 \uparrow + SO_2 + 2H_2O$
answered Jan 26, 2014 by mosymeow_1
 

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