# $2NaOD$ is also known as

$\begin{array}{1 1}(a)\;\text{Sodium oxide}&(b)\;\text{Densodium trioxide}\\(c)\;\text{Sodium deuteroxide}&(d)\;\text{Sodium diteroxide}\end{array}$

$2NaOD$ is also known as sodium deuteroxide.
Hence (c) is the correct answer.