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# Distance of the point $(\alpha,\beta,\gamma)$ from y-axis is \

$\begin{array}{1 1} (A)\;\beta\qquad(B)\;|\beta|\qquad(C)\;|\beta|+|\gamma|\qquad(D)\;\sqrt{\alpha^2+\gamma^2}\end{array}$

Toolbox:
• Drop perpendicular from the point to Y axis and XY plane.
• Join the foot of the perpendicular and the point to get right angle triangle.
• The distance required is hypotenuse after this $\Delta$
Ans : (D)

edited Apr 5, 2013