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The II group metal ion having $6s^2,6p^6$ as outer electron configuration is

$\begin{array}{1 1}(a)\;Ca^{+1}&(b)\;Sr^{++}\\(c)\;Ba^{++}&(d)\;Ra^{++}\end{array}$

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Ra has $6s^2,6p^67s^2$
$\Rightarrow Ra^{2+}$ is $6s^26p^6$
Hence (d) is the correct answer.
answered Jan 27, 2014 by sreemathi.v
 
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