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Electronic configuration in the valency shell of barium is

$\begin{array}{1 1}(a)\;5s^2&(b)\;6s^2\\(c)\;5s^1&(d)\;6s^1\end{array}$

1 Answer

Electronic configuration in the valency shell of barium is $6s^2$
Hence (b) is the correct answer.
answered Jan 27, 2014 by sreemathi.v
 
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