$(a)\;1.28 \times 10^{-5} m \\ (b)\;2.48 \times 10^{-5}\;m \\ (c)\;1.56 \times 10^{-5} m \\ (d)\;3.62 \times 10^{-5}m $

Want to ask us a question? Click here

Browse Questions

Ad |

0 votes

0 votes

To create a hole an electron must be given energy at least equal to 50 mev to go into acceptor level.

$\large\frac{hc}{\lambda}$$ \geq\; 50 mev$

$\lambda \geq \large\frac{hL}{50 mev}$

$\qquad= \large\frac{1242 ev\;nm}{50 \times 10^{-3} ev}$

$\qquad= 2.48 \times 10^{-5} \;m$

Hence b is the correct answer.

Ask Question

Tag:MathPhyChemBioOther

Take Test

x

JEE MAIN, CBSE, NEET Mobile and Tablet App

The ultimate mobile app to help you crack your examinations

...