Email
Chat with tutor
logo

Ask Questions, Get Answers

X
 
Answer
Comment
Share
Q)

A p type semiconductor has acceptor level of 50 mev above the valance band. Find the maximum wave length of light which can create a hole.

$(a)\;1.28 \times 10^{-5} m \\ (b)\;2.48 \times 10^{-5}\;m \\ (c)\;1.56 \times 10^{-5} m \\ (d)\;3.62 \times 10^{-5}m $

1 Answer

Comment
A)
To create a hole an electron must be given energy at least equal to 50 mev to go into acceptor level.
$\large\frac{hc}{\lambda}$$ \geq\; 50 mev$
$\lambda \geq \large\frac{hL}{50 mev}$
$\qquad= \large\frac{1242 ev\;nm}{50 \times 10^{-3} ev}$
$\qquad= 2.48 \times 10^{-5} \;m$
Hence b is the correct answer.
Help Clay6 to be free
Clay6 needs your help to survive. We have roughly 7 lakh students visiting us monthly. We want to keep our services free and improve with prompt help and advanced solutions by adding more teachers and infrastructure.

A small donation from you will help us reach that goal faster. Talk to your parents, teachers and school and spread the word about clay6. You can pay online or send a cheque.

Thanks for your support.
Continue
Please choose your payment mode to continue
Home Ask Homework Questions
Your payment for is successful.
Continue
Clay6 tutors use Telegram* chat app to help students with their questions and doubts.
Do you have the Telegram chat app installed?
Already installed Install now
*Telegram is a chat app like WhatsApp / Facebook Messenger / Skype.
...