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What is intensity of electric field in the depletion region of which $2.5 \times 10^{-7} m$ if the potential barrier is $0.50 v$

$(a)\;1 \times 10^6 \;vm^{-1} \\ (b)\;2 \times 10^{6} \;vm^{-1} \\ (c)\;1 \times 10^{-5}vm^{-1} \\ (d)\;2 \times 10^{+5} Vm^{-1} $

1 Answer

Electric field $E= \large\frac{v}{d}$
$\qquad= \large\frac{0.5 v}{2.5 \times 10^{-7} m } $
$\qquad= 2 \times 10^{6}m^{-1}$
Hence b is the correct answer.
answered Jan 27, 2014 by meena.p
 

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