# The sine of the angle between the straight line $\large \frac{x\;-2}{3}=\frac{y\;-3}{4}=\frac{z\;-4}{5}\;$ and the plane $2x-2y+z=5$ is
$(A)\;\frac{10}{6\sqrt 5}\qquad(B)\;\frac{4}{5\sqrt 2}\qquad(C)\;\frac{2\sqrt 3}{5}\qquad(D)\;\frac{\sqrt 2}{10}$