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The ratio of volume of the hydrogen liberated at S.T.P when equal amounts of tin reacts with dilute NaOH and conc NaOH.

$\begin{array}{1 1}(a)\;1 : 1&(b)\;1 : 2\\(c)\;2 : 1&(d)\;2 : 3\end{array}$

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$Sn+2NaOH(dil)+H_2O\rightarrow Na_2SnO_3(\text{sodium stannate})+2H_2$
$Sn+2NaOH(conc)\rightarrow Na_2SnO_2(\text{sodium stannite})+H_2$
Hence (c) is the correct answer.
answered Jan 27, 2014 by sreemathi.v
 
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