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unpaired electrons $(e^-)$ are present in

$\begin{array}{1 1}(a)\;BaO_2&(b)\;KO_2\\(c)\;K_2O&(d)\;Na_2O_2\end{array}$

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Super oxide ion.
$K_2O$
Hence (c) is the correct answer.
answered Jan 27, 2014 by sreemathi.v
 
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