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What is current and voltage across the diode in The given circuit given drift current is $ 2 \times 10^{-3}A$

 

$(a)\;0A,3V \\ (b)\;2 \times 10^{-3}\;A,4.6 V \\ (c)\;0A, 4.6V \\ (d)\;2.5 \times 10^{-2}A,2V $
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Since the diode is reverse biased the current in the circuit is only the drift current of $2 \times 10^{-3} \;A$
Voltage across diode $=V-IR$
$ \qquad= 5- \times (200\times 2 \times 10^{-3})$
$\qquad= 5- 0.4$
$\qquad = 4.6 V$
Hence b is the correct answer.
answered Jan 27, 2014 by meena.p
 

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