# What is current and voltage across the diode in The given circuit given drift current is $2 \times 10^{-3}A$

$(a)\;0A,3V \\ (b)\;2 \times 10^{-3}\;A,4.6 V \\ (c)\;0A, 4.6V \\ (d)\;2.5 \times 10^{-2}A,2V$

Since the diode is reverse biased the current in the circuit is only the drift current of $2 \times 10^{-3} \;A$
Voltage across diode $=V-IR$
$\qquad= 5- \times (200\times 2 \times 10^{-3})$
$\qquad= 5- 0.4$
$\qquad = 4.6 V$
Hence b is the correct answer.