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Home  >>  CBSE XII  >>  Math  >>  Three Dimensional Geometry
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The vector equation of the line $\Large \frac{x-5}{3}\;\frac{y-4}{7}\;\frac{z-6}{2}$ is _______________.

$\begin{array}{1 1}(A)\;(x-5) \hat i-(y+4) \hat j-(z-6) \hat k=\lambda(3 \hat i+7 \hat j+2 \hat k) \\ (B)\;(x-5) \hat i+(y+4) \hat j+(z-6) \hat k=\lambda(3 \hat i+7 \hat j+2 \hat k) \\ (C)\;(x-5) \hat i-(y+4) \hat j+(z-6) \hat k=-\lambda(3 \hat i+7 \hat j+2 \hat k) \\(D)\;(x-5) \hat i+(y+4) \hat j+(z-6) \hat k=\lambda(3 \hat i-7 \hat j-2 \hat k) \end{array} $

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$(B)\;(x-5) \hat i+(y+4) \hat j+(z-6) \hat k=\lambda(3 \hat i+7 \hat j+2 \hat k)$
answered Nov 7, 2013 by pady_1
 

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