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Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class11  >>  Statistics
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For $a$ series the value of mean deviation is 15. The most likely value of its quartile deviation is

$\begin {array} {1 1} (A)\;12.5 & \quad (B)\;11.6 \\ (C)\;13 & \quad (D)\;9.7 \end {array}$

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1 Answer

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Since $ MD = \large\frac{4}{5}$ $ \sigma$
$ QD = \large\frac{2}{3}$ $ \sigma$
$ \large\frac{MD}{QD} = \large\frac{6}{5}$
$ \Rightarrow QD = \large\frac{5}{6}$ $ MD$
$ = \large\frac{5}{6} $ $ (15)$
$ = 12.5$
Hence Ans : (A)
answered Jan 27, 2014 by thanvigandhi_1
 

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