# For $a$ series the value of mean deviation is 15. The most likely value of its quartile deviation is

$\begin {array} {1 1} (A)\;12.5 & \quad (B)\;11.6 \\ (C)\;13 & \quad (D)\;9.7 \end {array}$

## 1 Answer

Since $MD = \large\frac{4}{5}$ $\sigma$
$QD = \large\frac{2}{3}$ $\sigma$
$\large\frac{MD}{QD} = \large\frac{6}{5}$
$\Rightarrow QD = \large\frac{5}{6}$ $MD$
$= \large\frac{5}{6}$ $(15)$
$= 12.5$
Hence Ans : (A)
answered Jan 27, 2014

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