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# $Li,Na$ and $K$ burn is excess of air to form

$\begin{array}{1 1}(a)\;Li_2O,Na_2O,K_2O\\(b)\;Li_2O,Na_2O_2\\(c)\;Li_2O,Na_2O_2,KO_2\\(d)\;Li_2O,NaO_2,K_2O_2\end{array}$

$Li,Na$ and $K$ burn is excess of air to form $Li_2O,Na_2O_2$
Hence (b) is the correct answer.