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On heating a mixture of potassium dichromate and sodium chloride with concentrated sulphuric acid in a dry test tube, the compound formed

(a) Chromium chloride
(b) Chromyl chloride
(c) Chlorice dioxide
(d) Chromic acid

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Answer: Chromyl chloride
 
$4NaCl(s) + K_2Cr_2O_7(s) + 3H_2SO_4(l) \overset{\Delta}{\longrightarrow} $
$K_2SO_4 \text{{Potassium sulphate}} + 2NaSO_4 \text{{Sodium sulphate}} + 2CrO_2Cl_2 \text{{Chromyl chloride, Orange red}} + 3H_2O$
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