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# Consider the following reaction $6NaOH+3Cl_2\rightarrow 5NaCl+A+3H_2O$ what is the oxidation number of chlorine in "A"?

$\begin{array}{1 1}(a)\;+5&(b)\;-1\\(c)\;+3&(d)\;+1\end{array}$

$3Cl_2^0+6NaOH\rightarrow 5NaCl+NaCl^{+5}O_3+3H_2O$
Hence (a) is the correct answer.