Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

In the use of transistor as an amplifier $I_f \alpha =\large\frac{I_c}{I_e}$ and $\beta =\large\frac{I_c}{I_b}$ where $I_c$- collector current $I_b$- base current $I_e$- emitter current then

$(a)\;\beta= \large\frac{1+\alpha}{\alpha} \\ (b)\;\beta = \frac{\alpha}{1+\alpha} \\ (c)\;\beta =\frac{1- \alpha}{\alpha} \\ (d)\;beta = \frac{\alpha}{1- \alpha} $
Can you answer this question?

1 Answer

0 votes
$I_c= I_c+I_b$
$\therefore \large\frac{I_e}{I_c} =\frac{I_c +I_b}{I_c}$
$\qquad= 1+ \large\frac{I_b}{I_c}$
=> $\large\frac{1}{\alpha} =1+\large\frac{1}{\beta}$
$\therefore \beta=\large\frac{\alpha}{1- \alpha}$
Hence d is the correct answer.
answered Jan 28, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App