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In the hardening stage of plaster of paris,the compound formed is

$\begin{array}{1 1}(a)\;CaSO_4\\(b)\;Orthorhomic\; CaSO_4.2H_2O\\(c)\;CaSO_4.H_2O\\(d)\;Monoclinic\;CaSO_4.2H_2O\end{array}$

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Monoclinic $CaSO_4.2H_2O$
Hence (d) is the correct answer.
answered Jan 28, 2014 by sreemathi.v
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