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Hardening of plaster of paris is because of

$\begin{array}{1 1}(a)\;\text{The formation of }CaCO_3\\(b)\;\text{The formation of }CaSiO_3\\(c)\;\text{The transition of orthorhombic gypsum to monoclinic gypsum}\\(d)\;\text{Dehydration}\end{array}$

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Hardening is due to transition of orthorhombic gypsum into monoclinic gypsum.
Hence (c) is the correct answer.
answered Jan 28, 2014 by sreemathi.v
 
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