If $x$ and $y$ are connected parametrically by the equations given in $x = 4t, \: y = \large\frac{4}{t} $ without eliminating the parameter, Find $\large\frac{dy}{dx}$

Question

$\begin{array}{1 1} \frac{-1}{t^3} \\\frac{1}{t^2} \\\frac{-1}{t^2} \\\frac{1}{t^3}\end{array} $