Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

What is the output resistance, When we observe in a common emitter circuit the collector current increase from $9.5 \;mA\;to 10\;mA$ When the collector voltage increase from $2.5 \;to \;6v$ When base current is kept constant .

$(a)\;7.5 K\; \Omega \\ (b)\;8.5 k \; \Omega \\ (c)\;3.2 k \;\Omega \\ (d)\;7.0 k\; \Omega $
Can you answer this question?

1 Answer

0 votes
Output resistance $r_0=\large\frac{\Delta V_{cE}} {\Delta I _c}$
$\qquad= \large\frac{(6- 2.5)v}{(10-9.5 )m A}$
$\qquad= \large\frac{3.5 \;v}{0.5 mA}$
$\qquad= 7 k \Omega$
Hence d is the correct answer.
answered Jan 28, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App