Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

A transistor in common emitted mode the load resistance is $2k \Omega$ and the current gain $\beta =50,$ What is the power if input resistance is $500 \Omega$

$(a)\;10^2 \\ (b)\;10^3 \\ (c)\;10^4 \\ (d)\;10^5 $
Can you answer this question?

1 Answer

0 votes
Power gain $= \beta ^2 \times \large\frac{R_{\Large output}}{R_{\Large input}}$
$\qquad= (50)^2 \times \large\frac{2}{0.5}$
$\qquad= 10^4$
Hence c is the correct answer.
answered Jan 28, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App