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A transistor in common emitted mode the load resistance is $2k \Omega$ and the current gain $\beta =50,$ What is the power if input resistance is $500 \Omega$

$(a)\;10^2 \\ (b)\;10^3 \\ (c)\;10^4 \\ (d)\;10^5 $
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Power gain $= \beta ^2 \times \large\frac{R_{\Large output}}{R_{\Large input}}$
$\qquad= (50)^2 \times \large\frac{2}{0.5}$
$\qquad= 10^4$
Hence c is the correct answer.
answered Jan 28, 2014 by meena.p

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