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A metal salt solution forms a yellow precipitate with potassium chromate in acetic acid, a white precipitate with dilute $H_2SO_4$ but gives no precipitate with sodium chloride or iodide, it is

(a) Lead carbonate
(b) Basic lead carbonate
(c) Barium carbonate
(d) Strontium carbonate
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Answer: Barium carbonate
$BaCO_3 + 2CH_3COOH \longrightarrow Ba(CH_3COO)_2 + CO_2 + H_2O$
$Ba(CH_3COO)_2 + K_2CrO_4 \longrightarrow BaCrO_4 \downarrow (\text{Yellow ppt.}) + 2KOOCCH_3$
$BaCO_3 + H_2SO_4 \longrightarrow BaSO_4 \downarrow (\text{White ppt.}) + 2CO_2 + 2H_2O$
answered Jan 28, 2014 by mosymeow_1

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