Browse Questions

# The energy density of an ideal monoatomic gas is equal to:

(A) $3P$ (B) $\large\frac{3}{2}$$P (C) \large\frac{1}{2}$$P$ (D) $2P$

Energy of a gas $= \large\frac{nfRT}{2}$
For a monoatomic gas, $f = 3 \rightarrow u = \large\frac{3}{2}$$nRT$$= \large\frac{3}{2}$$PV \Rightarrow \large\frac{u}{v}$$ = \large \frac{3}{2}$$P$