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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Kinetic Theory of Gases
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The energy density of an ideal monoatomic gas is equal to:

(A) $3P$ (B) $\large\frac{3}{2}$$P$ (C) $\large\frac{1}{2}$$P$ (D) $ 2P $
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1 Answer

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Energy of a gas $ = \large\frac{nfRT}{2}$
For a monoatomic gas, $f = 3 \rightarrow u = \large\frac{3}{2}$$nRT$$= \large\frac{3}{2}$$PV$
$\Rightarrow \large\frac{u}{v}$$ = \large \frac{3}{2}$$P$
answered Jan 28, 2014 by balaji.thirumalai
 

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