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Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class11  >>  Statistics
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For 12 pair of observation on $x$ and $y$ the $r$ calculated is $0.674$. The standard error is

$\begin {array} {1 1} (A)\;0.2563 & \quad (B)\;0.1575 \\ (C)\;0.4384 & \quad (D)\;None\: of \: these \end {array}$

Can you answer this question?
 
 

1 Answer

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Using the formula of standard error we get
SE = $ \large\frac{1-r^2}{\sqrt n}$
$ = \large\frac{1-(0.674)^2}{\sqrt {12}}$
$ = \large\frac{1-0.45}{3.46}$
$ = 0.1589$
Ans : (D)
answered Jan 28, 2014 by thanvigandhi_1
 

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