Browse Questions

# For 12 pair of observation on $x$ and $y$ the $r$ calculated is $0.674$. The standard error is

$\begin {array} {1 1} (A)\;0.2563 & \quad (B)\;0.1575 \\ (C)\;0.4384 & \quad (D)\;None\: of \: these \end {array}$

Using the formula of standard error we get
SE = $\large\frac{1-r^2}{\sqrt n}$
$= \large\frac{1-(0.674)^2}{\sqrt {12}}$
$= \large\frac{1-0.45}{3.46}$
$= 0.1589$
Ans : (D)