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The transconductance of a transistor used as an amplifier in common emitter mode is $0.1 \;mho.$ When a signal of 10 mv is added to base emitter voltage change in collector current is

$(a)\;1\;A \\ (b)\;0.1 \;A \\ (c)\;1\;mA \\ (d)\;0.1 \;mA $
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trans conductance $g_m=\large\frac{\Delta I_c}{\Delta V_{BE}}$
$0.1 = \large\frac{\Delta I_c}{10\;mV}$
$\Delta I_c= 0.1 \times 10 mA$
$\qquad= 1 mA$
Hence c is the correct answer.
answered Jan 28, 2014 by meena.p

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