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The pair of amphoteric hydroxides is :

$\begin{array}{1 1}(a)\;Be(OH)_2,Zn(OH)_2\\(b)\;Al(OH)_3,LiOH\\(c)\;B(OH)_3,B(OH)_2\\(d)\;Be(OH)_2,Mg(OH)_2\end{array}$

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Down IIA,solubility of sulphates decreases and $BaSO_4$ is heavier than $CaSO_4$
Hence (b) is the correct answer.
answered Jan 29, 2014 by sreemathi.v
 
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