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When the separation between two charges is increased the electric potential energy of the charges

$(a)\;increase\qquad(b)\;decrease\qquad(c)\;remains\;same\qquad(d)\;may\;increase\;or\;decrease$

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  • The SI unit of quantity of electric charge is the coulomb, which is equivalent to about $6.242 \times 10^{18}$ e (e is the charge of a proton). Hence, the charge of an electron is approximately $?1.602 \times 10^{?19}$ C.
Answer : (d) may increase or decrease
Potential energy between two charges $\;\sqcup (r)=\large\frac{k q_{1} q_{2}}{r}$
Now if r increases and $\;q_{1} \;and\;q_{2}\;$ are of same sign then $\;\sqcup (r)\;decrases\;.\;Else\;if\;q_{1}\;and\;q_{2}\;are\;of\;opposite\;signs\;\sqcup (r)\;increases\;.$
Therefore depending on signs of $\;q_{1}\;and\;q_{2}\;\sqcup (r)\;may\;increase];or\;decrease\;.$
answered Jan 29, 2014 by yamini.v 1 flag
edited Jan 30, 2014 by yamini.v
 

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