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Which of the following statements regarding transition elements is/are incorrect?

(1) $Cu^{2+}(3d^{10})$ is more stable than $Cu(I)$ though $Cu(I)$ has a $3d^{10}$ electronic-configuration

(2) $Cu^{2+}(3d^{10})$ is less stable than $Cu(I)$ because $Cu(I)$ has a $3d^{10}$ electronic-configuration (3) A 4s sub-shell is filled prior to 3d but on ionization, 4s electrons are removed (4) A 4s sub-shell is not filled prior to 3d and on ionization, 4s electrons are removed

$\begin{array}{1 1} Cu \\ Zn \\ Sc \\ Mn\end{array}$

1 Answer

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Answer: (2) and (4) are incorrect.
(2): The opposite is true because of the small size and high charge on $Cu (II)$ it has a higher value of lattice and hydration energies which result in greater stability of $Cu^{2+}$ as compared to $Cu(I)$
(4): The 4s subshell is filled prior to 3d as explained by the n+1 rule. However when it comes to ionization of electrons, 4s is removed prior to 3d as it has lower value of Ionization Energy.
answered Jan 29, 2014 by sreemathi.v
edited Jul 29, 2014 by balaji.thirumalai
 

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