info@clay6.com
logo

Ask Questions, Get Answers

X
 
Answer
Comment
Share
Q)

Which of the following statements regarding transition elements is/are incorrect?

(1) $Cu^{2+}(3d^{10})$ is more stable than $Cu(I)$ though $Cu(I)$ has a $3d^{10}$ electronic-configuration

(2) $Cu^{2+}(3d^{10})$ is less stable than $Cu(I)$ because $Cu(I)$ has a $3d^{10}$ electronic-configuration (3) A 4s sub-shell is filled prior to 3d but on ionization, 4s electrons are removed (4) A 4s sub-shell is not filled prior to 3d and on ionization, 4s electrons are removed

$\begin{array}{1 1} Cu \\ Zn \\ Sc \\ Mn\end{array}$

1 Answer

Comment
A)
Need homework help? Click here.
Answer: (2) and (4) are incorrect.
(2): The opposite is true because of the small size and high charge on $Cu (II)$ it has a higher value of lattice and hydration energies which result in greater stability of $Cu^{2+}$ as compared to $Cu(I)$
(4): The 4s subshell is filled prior to 3d as explained by the n+1 rule. However when it comes to ionization of electrons, 4s is removed prior to 3d as it has lower value of Ionization Energy.
Home Ask Homework Questions
...